Trains
and Work
1. Two trains running in opposite directions cross a man standing on
the platform in 27 seconds and 17 seconds respectively . If they cross each
other in 23 seconds, what is the ratio of their speeds?
A. Insufficient data B. 3
: 1
C. 1 : 3 D. 3 : 2
2. A jogger is running at 9 kmph
alongside a railway track in 240 meters ahead of the engine of a 120 meters
long train . The train is running at 45 kmph in the same direction. how much
time does it take for the train to pass the jogger?
A. 46 B. 36
C. 18 D. 22
3. A train passes a platform in
36 seconds. The same train passes a man standing on the platform in 20 seconds.
If the speed of the train is 54 km/hr, The length of the platform is
A. None of these B.
280 meter
C. 240 meter D. 200 meter
4. Two trains, one from P to Q
and the other from Q to P, start simultaneously. After they meet, the trains
reach their destinations after 9 hours and 16 hours respectively. The ratio of
their speeds is
A. 2 : 3 B. 2 :1
C. 4 : 3 D. 3 : 2
5. A train having a length of 1/4 mile , is traveling at a speed of 75
mph. It enters a tunnel 3 ½ miles long. How long does it take the train to pass
through the tunnel from the moment the front enters to the moment the rear
emerges?
A. 3 min B. 4.2 min
C. 3.4 min D. 5.5 min
6. A train overtakes two persons who are walking in the same direction
to that of the train at 2 kmph and 4 kmph and passes them completely in 9 and
10 seconds respectively. What is the length of the train?
A. 62 m B. 54 m
C. 50 m D. 55 m
7. Two trains, each 100 m long are moving in opposite directions. They
cross each other in 8 seconds. If one is moving twice as fast the other, the
speed of the faster train is
A. 75 km/hr B. 60 km/hr
C. 35 km/hr D. 70 km/hr
8. Two stations P and Q are 110 km apart on a straight track. One train
starts from P at 7 a.m. and travels towards Q at 20 kmph. Another train starts
from Q at 8 a.m. and travels towards P at a speed of 25 kmph. At what time will
they meet?
A. 10.30 a.m B. 10 a.m.
C. 9.10 a.m. D. 11 a.m.
9. A train 108 m long is moving
at a speed of 50 km/hr . It crosses a train 112 m long coming from opposite
direction in 6 seconds. What is the speed of the second train?
A. 82 kmph B. 76 kmph
C. 44 kmph D. 58 kmph
10. 32. Two trains are
approaching each other with the speed of 25km/hr. and 30km/hr. respectively
from two different stations A and B. When two trains will meet each other, the
second train had covered 20 km more than the first train. What is the distance
between A and B stations?
A. 220 km
B. 200km
C. 440 km
D. 100 km
11. P is able to do a piece of work in 15 days and Q can do the same
work in 20 days. If they can work together for 4 days, what is the fraction of
work left?
A. 8/15 B. 7/15
C. 11/15 D. 2/11
12. P can lay railway track between two stations in 16 days. Q can do
the same job in 12 days. With the help of R, they completes the job in 4 days.
How much days does it take for R alone to complete the work?
A. 9(3/5) days B. 9(1/5) days
C. 9(2/5) days D. 10 days
13. P, Q and R can do a work in 20, 30 and 60 days respectively. How
many days does it need to complete the work if P does the work and he is
assisted by Q and R on every third day?
A. 10 days B. 14 days
C. 15 days D. 9 days
14. A is thrice as good as B in
work. A is able to finish a job in 60 days less than B. They can finish the
work in - days if they work together.
A. 18 days B. 22 ½ days
C. 24 days D. 26 days
15. A can do a particular work in 6 days . B can do the same work in 8
days. A and B signed to do it for Rs. 3200. They completed the work in 3 days
with the help of C. How much is to be paid to C?
A. Rs. 380 B. Rs. 600
C. Rs. 420 D. Rs. 400
16. 6 men and 8 women can complete a work in 10 days. 26 men and 48
women can finish the same work in 2 days. 15 men and 20 women can do the same
work in - days.
A. 4 days B. 6 days
C. 2 days D. 8 days
17. A completes 80% of a work in 20 days. Then B also joins and A and B
together finish the remaining work in 3 days. How long does it need for B if he
alone completes the work?
A. 37 ½ days B. 22 days
C. 31 days D. 22 days
18. P is 30% more efficient than Q. P can complete a work in 23 days.
If P and Q work together, how much time will it take to complete the same work?
A. 9 B. 11
C. 13 D. 15
19. If daily wages of a man is double to that of a woman, how many men
should work for 25 days to earn Rs.14400? Given that wages for 40 women for 30
days are Rs.21600.
A. 12 B. 14
C. 16 D. 18
20. There is a group of persons each of whom can complete a piece of
work in 16 days, when they are working individually. On the first day one
person works, on the second day another person joins him, on the third day one
more person joins them and this process continues till the work is completed.
How many days are needed to complete the work?
A. 3 1⁄4 days B. 4 1⁄3 days
C. 5 1⁄6 days D. 6 1⁄5 days
Answers
1.
Answer :
Option D
Explanation :
Let the speed of the trains be x and y respectively
length of train1 = 27x
length of train2 = 17y
Relative speed= x+ y
Time taken to cross each other = 23 s
=> (27x + 17 y)/(x+y) = 23
=> (27x + 17 y)/ = 23(x+y)
=> 4x = 6y
=> x/y = 6/4 = 3/2
2.
Answer :
Option B
Explanation :
Distance to be covered = 240+ 120 = 360 m
Relative speed = 36 km/hr = 36×10/36 = 10 m/s
Time = distance/speed = 360/10 = 36 seconds
3.
Answer : Option C
Explanation :
Speed of the train = 54 km/hr = (54×10)/36 m/s = 15 m/s
Length of the train = speed × time taken to cross the man = 15×20 = 300
m
Let the length of the platform = L
Time taken to cross the platform = (300+L)/15
=> (300+L)/15 = 36
=> 300+L = 15×36 = 540
=> L = 540-300 = 240 meter
4.
Answer :
Option C
Explanation :
Ratio of their speeds = Speed of first train : Speed of second train
= √16−−√9
= 4:3
5.
Answer :
Option A
Explanation :
Total distance = 3 ½ + ¼ = 7/2 + ¼ = 15/4 miles
Speed = 75 mph
Time = distance/speed = (15/4) / 75 hr = 1/20 hr = 60/20 minutes = 3
minutes
6.
Answer :
Option C
Explanation :
Let x is the length of the train in meter and v is its speed in kmph
x/9 = ( v-2)(10/36) ---(1)
x/10 =( v-4) (10/36) --- (2)
Dividing equation 1 with equation 2
10/9 = (v-2)/(v-4)
=> 10v - 40 = 9v - 18
=> v = 22
Substituting in equation 1, x/9 = 200/36 => x = 9×200/36 = 50 m
7.
Answer :
Option B
Explanation :
Total distance covered = 100+100 = 200 m
Time = 8 s
let speed of slower train is v . Then the speed of the faster train is
2v
(Since one is moving twice as fast the other)
Relative speed = v + 2v = 3v
3v = 200/8 m/s = 25 m/s
=> v = 25/3 m/s
Speed of the faster train = 2v = 50/3 m/s = (50/3)×(36/10) km/hr
=> 5×36/3 = 5×12 = 60 km/hr
8.
Answer :
Option B
Explanation :
Assume both trains meet after x hours after 7 am
Distance covered by train starting from P in x hours = 20x km
Distance covered by train starting from Q in (x-1) hours = 25(x-1)
Total distance = 110
=> 20x + 25(x-1) = 110
=> 45x = 135
=> x= 3
Means, they meet after 3 hours after 7 am, ie, they meet at 10 am
9.
Answer :
Option A
Explanation :
Total distance = 108+112 = 220 m
Time = 6s
Relative speed = distance/time = 220/6 m/s = 110/3 m/s
= (110/3) × (18/5) km/hr = 132 km/hr
=> 50 + speed of second train = 132 km/hr
=> Speed of second train = 132-50 = 82 km/hr
10.
Answer :
Option A
Explanation :
Relative Difference : Distance1 - Distance2 = 20 km
Speed1 - Speed2 = 5km/hr
So, Time = Distance/Speed
= 20km/5
Time = 4 hrs.
Now, Distance is equal to Speed x Time.
(30km/hr + 25km/hr)x4
= 55x4
Ans = 220 km.
Or
Let the distance traveled by the first train and second train be x and
(x+20) respectively.
Since time taken by both trains are same when they meet each other,
x/25 = (x+20)/30
x/5 = (x+20)/6
6x = 5x + 100
x = 100
Distance between A and B = x + (x+20) = 220 km
11.
Answer :
Option A
Explanation :
Amount of work P can do in 1 day = 1/15
Amount of work Q can do in 1 day = 1/20
Amount of work P and Q can do in 1 day = 1/15 + 1/20 = 7/60
Amount of work P and Q can together do in 4 days = 4 × (7/60) = 7/15
Fraction of work left = 1 – 7/15= 8/15
12. Answer : Option A
Explanation :
Amount of work P can do in 1 day = 1/16
Amount of work Q can do in 1 day = 1/12
Amount of work P, Q and R can together do in 1 day = 1/4
Amount of work R can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 =
5/48
=> Hence R can do the job on 48/5 days = 9 (3/5) days
12.
Answer :
Option C
Explanation :
Amount of work P can do in 1 day = 1/20
Amount of work Q can do in 1 day = 1/30
Amount of work R can do in 1 day = 1/60
P is working alone and every third day Q and R is helping him
Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60)
= 1/5
So work completed in 15 days = 5 × 1/5 = 1
Ie, the work will be done in 15 days
13.
Answer :
Option B
Explanation :
If A completes a work in 1 day, B completes the same work in 3 days
Hence, if the difference is 2 days, B can complete the work in 3 days
=> if the difference is 60 days, B can complete the work in 90 days
=> Amount of work B can do in 1 day= 1/90
Amount of work A can do in 1 day = 3 × (1/90) = 1/30
Amount of work A and B can together do in 1 day = 1/90 + 1/30 = 4/90 =
2/45
=> A and B together can do the work in 45/2 days = 22 ½ days
14.
Answer :
Option D
Explanation :
Amount of work A can do in 1 day = 1/6
Amount of work B can do in 1 day = 1/8
Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24
Amount of work A + B + C can do = 1/3
Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24
work A can do in 1 day: work B can do in 1 day: work C can do in 1 day
= 1/6 : 1/8 : 1/24 = 4 : 3 : 1
Amount to be paid to C = 3200 × (1/8) = 400
15.
Answer :
Option A
Explanation :
Let work done by 1 man in 1 day = m and work done by 1 woman in 1 day =
b
Work done by 6 men and 8 women in 1 day = 1/10
=> 6m + 8b = 1/10
=> 60m + 80b = 1 --- (1)
Work done by 26 men and 48 women in 1 day = 1/2
=> 26m + 48b = ½
=> 52m + 96b = 1--- (2)
Solving equation 1 and equation 2. We get m = 1/100 and b = 1/200
Work done by 15 men and 20 women in 1 day
= 15/100 + 20/200 =1/4
=> Time taken by 15 men and 20 women in doing the work = 4 days
16.
Answer :
Option A
Explanation :
Work done by A in 20 days = 80/100 = 8/10 = 4/5
Work done by A in 1 day = (4/5) / 20 = 4/100 = 1/25 --- (1)
Work done by A and B in 3 days = 20/100 = 1/5 (Because remaining 20% is
done in 3 days by A and B)
Work done by A and B in 1 day = 1/15 ---(2)
Work done by B in 1 day = 1/15 – 1/25 = 2/75
=> B can complete the work in 75/2 days = 37 ½ days
17.
Answer :
Option C
Explanation :
Work done by P in 1 day = 1/23
Let work done by Q in 1 day = q
q × (130/100) = 1/23
=> q = 100/(23×130) = 10/(23×13)
Work done by P and Q in 1 day = 1/23 + 10/(23×13) = 23/(23×13)= 1/13
=> P and Q together can do the work in 13 days
18.
Answer :
Option B
Explanation :
Work done by P in 1 day = 1/24
Work done by Q in 1 day = 1/6
Work done by R in 1 day = 1/12
Work done by P,Q and R in 1 day = 1/24 + 1/6 + 1/12 = 7/24
=> Working together, they will complete the work in 24/7 days = 3
3⁄7 days
19.
Answer :
Option C
Explanation :
Wages of 1 woman for 1 day = 21600/40×30
Wages of 1 man for 1 day = 21600×2/40×30
Wages of 1 man for 25 days = 21600×2×25/40×30
Number of men = 14400/(21600×2×25/40×30)=144/(216×50/40×30)=144/9=16
20.
Answer :
Option C
Explanation :
Work completed in 1st day = 1/16
Work completed in 2nd day = (1/16) + (1/16) = 2/16
Work completed in 3rd day = (1/16) + (1/16) + (1/16) = 3/16
An easy way to attack such problems is from the choices. You can see
the choices are very close to each
other. So just see one by one.
For instance, The first choice given in 3 1⁄4
The work done in 3 days = 1/16 + 2/16 + 3/16 = (1+2+3)/16 = 6/16
The work done in 4 days = (1+2+3+4)/16 = 10/16
The work done in 5 days = (1+2+3+4+5)/16 = 15/16, almost close, isn't it?
The work done in 6 days = (1+2+3+4+5+6)/16 > 1
Hence the answer is less than 6, but greater than 5. Hence the answer
is 5 1⁄6 days.
(Just for your reference, work done in 5 days = 15/16.
Pending work in 6th day = 1 – 15/16 = 1/16.
In 6th day, 6 people are working and work done = 6/16.
To complete the work 1/16, time required = (1/16) / (6/16) = 1/6 days.
Hence total time required = 5 + 1/6 = 5 1⁄6 days
No comments:
Post a Comment
Note: Only a member of this blog may post a comment.